okay,let's simplify that.if secx=cscx,it will be also true that cosx=sinx.
in first quadrant,[tex] \pi [/tex]/4 could be an answer
in second quadrant,sin is positive but cos is negative.so,there is NO such angle
in third quadrant,([tex] \pi
[/tex]+[tex] \pi [/tex]/4) is a answer(where both of them are negative)
in fourth quadrant,cos is positive but sin negative...so there isnt any angle.
[tex] \pi /4, 5 \pi /4[/tex] are the answers
