[tex]\bf \cfrac{\quad \frac{n-3}{n^2+6n+8}\quad }{\frac{n+1}{n+2}}\implies
\cfrac{\quad \frac{n-3}{(n+4)(n+2)}\quad }{\frac{n+1}{n+2}}\implies \cfrac{n-3}{(n+4)\underline{(n+2)}}\cdot \cfrac{\underline{n+2}}{n+1}
\\\\\\
\cfrac{n-3}{(n+4)(n+1)}\implies \cfrac{n-3}{n^2+5n+4}[/tex]
