This will be a third degree polynomial since we have 3 zeros. We will FOIL them out. They are: (x-2), (x+7i), (x-7i). The product of the second and third factors gives us [tex]x^2-49i^2[/tex]. i^2 = -1, so if we simplify, we have [tex]x^2-49(-1)=x^2+49[/tex]. Now we will multiply that with x-2 to get [tex]x^3-2x^2+49x-98[/tex]. There you go!
