Given P(E) = 0.24 and P(F ∩ E) = 0.17
It says to find conditional probability of F given E has occurred.
We know the formula of conditional probability is given by :-
P(F ║ E) = [tex] \frac{P(E\;and\; F)}{P(E)} [/tex]
P(F ║ E) = [tex] \frac{0.17}{0.24} [/tex] = 0.708333
P(F ║ E) = 0.71
Hence, option C i.e. 0.71 is the final answer.
