The general equation of circle with center (a,b) and radius r is given by
[tex] (x-a)^2+(y-b)^2=r^2 [/tex]
We know that radius = diameter /2 =10/2=5
Thus the equation of circle with center (-3,5) and radius 5 is given by
[tex] (x-(-3))^2+(y-5)^2=5^2 [/tex]
[tex] (x+3)^2+(y-5)^2=25 [/tex]
When expanding this, we get
x^2+6x+9+y^2-10y+25=25
x^2+y^2+6x-10y+9=0
This is the required equation of circle.
