The circle has center at (9, 12) and passes through the origin.
Equation of the circle in center and radius form is given by
[tex] (x-h)^2+(y-k)^2=r^2 [/tex]
where r is the radius and center at (h,k)
Now substitute the value of the center we get
[tex] (x-9)^2+(y-12)^2=r^2 [/tex]
As it passes through the origin so we can write
[tex] (0-9)^2+(0-12)^2=r^2\\
\\
81+144=r^2\\
\\
225=r^2\\
\\
r=15\\ [/tex]
Hence the equation of the circle is
[tex] (x-9)^2+(y-12)^2=15^2 [/tex]
