we know that
formula of each interior angle of regular polygons
[tex] \theta=\frac{180(n-2)}{n} [/tex]
where
theta is angle
n is number of sides
we are given
theta=108
so, we can set it equal
[tex] 108=\frac{180(n-2)}{n} [/tex]
now, we can solve for n
[tex] 108n=180(n-2) [/tex]
[tex] 108n=180n-360 [/tex]
[tex] 72n=360 [/tex]
[tex] n=5 [/tex]
so, option-A...........Answer
