we are given with the inequality
[tex] (3x+5)(x-1) < 2x+7\\
\\
[/tex]
Open the parenthesis we get on left side we get
[tex] (3x+5)(x-1) < 2x+7 =3x^2-3x+5x-5<2x+7\\
\\
3x^2+2x-5<2x+7\\
\\
\text{Add -2x-7 on both the sides we get}\\
\\
3x^2+2x-5-2x-7<2x+7-2x-7\\
\\
3x^2-12<0\\
\\
\text{Add 12 on both the sides we get}\\
\\
3x^2<12\\
\\
\text{Divide both the sides by 3 we get}\\
\\
x^2<4\\
\\
-2<x<2\\ [/tex]
