[tex]<b>HEY MATE !![/tex]
Secx = [tex]\frac{25}{24}[/tex]
As we know secx = hypotenuse/ perpendicular
And cotx = Base / perpendicular
So now we have to find BASE .
[tex]{25}^{2}= {B}^{2}+ {24}^{2}[/tex]
625= [tex]{B}^{2}[/tex]+ 576
[tex]{B}^{2}[/tex] = 625 - 576
[tex]{B}^{2}[/tex] = 49
Taking squre root on both sides.
B = 7
Now cotx = 24/ 7
SO YOUR ANSWER IS OPTION . (C)
HOPE YOU LIKED.
