If you plug in the x and y values for the points (X,Y).
Then you are able to solve for the equation by seeing whether or not it equals the Y value.
Ex. Solving 9a.
Step One Equation and Point (2,0) or (X,Y)
[tex]y = ({x})^{2} - 3(x) + 2[/tex]
Step 2 Plug in and solve
[tex]0 = {2}^{2} - 3(2) + 2[/tex]
0=4-6+2
0=0
Done and Answer is Yes it does fit.
