Answer:
1 or -1 if written [tex]-(9x)^{0}[/tex]
Step-by-step explanation:
Anything to the power of 0 is 1.
if the problem is written -(9x)[tex]^{0}[/tex] though it would be negative one because the negative is outside of the parenthesis.
-1
- (9x) ^ 0
The item inside the parentheses is raised to the power
The negative is outside of the exponent
-1 * (9x)^0
PEMDAS says powers first.
Anything to the zero power is 1
-1 * 1
