Answer:
[tex]\huge\boxed{x^3-3x^2-13x+15}[/tex]
Step-by-step explanation:
[tex]\text{Use FOIL:}\\\\(a+b)(c+d)=ac+ad+bc+bd[/tex]
[tex](x+3)(x^2-6x+5)\\\\=(x)(x^2)+(x)(-6x)+(x)(5)+(3)(x^2)+(3)(-6x)+(3)(5)\\\\=x^3-6x^2+5x+3x^2-18x+15\\\\\text{combine like terms}\\\\=x^3+(-6x^2+3x^2)+(5x-18x)+15\\\\=x^3-3x^2-13x+15[/tex]
