Answer:
C. (0,-5) and (0,5)
Step-by-step explanation:
The y-intercepts are the values of the function when x = 0. Its the point (0,b). To find them, substitute x =0 into the equation.
[tex]\frac{x^2}{100}+\frac{x^2}{25} =1 \\\frac{0^2}{100}+\frac{x^2}{25} =1 \\\frac{0}{100}+\frac{x^2}{25} =1 \\0+ \frac{x^2}{25} =1 \\ \frac{x^2}{25} =1 \\x^2=1*25\\x^2=25\\x=-5,5[/tex]
The y-intercepts are (0,-5) and (0,5).
