Answer:
x = - [tex]\frac{1}{2}[/tex] with multiplicity 2
Step-by-step explanation:
given 4x² + 4x + 1 = 0
This is a perfect square of the type
(a + b)² = a² + 2ab + b²
4x² = (2x)² ⇒ a = 2x, 1 = 1² ⇒ b = 1, and
2ab = 2 × 2x × 1 = 4x
4x² + 4x + 1 = 0
(2x + 1)² = 0, hence
x = - [tex]\frac{1}{2}[/tex] with multiplicity 2
