Answer:
Step-by-step explanation:
Put x = -3 to the equation of a function H(x):
[tex]H(x)=4x^2-5x\\\\H(-3)=4(-3)^2-5(-3)=4(9)+15=36+15=51[/tex]
51
H(x)=4x^2-5x
Let x=-3
H(-3) = 4(-3)^2 -5(-3)
Powers first
= 4(9) -5(-3)
=36+15
=51
