Answer:
[tex]y + 2= -\frac{1}{3}(x-5)[/tex]
Step-by-step explanation:
To write the equation of a line with a slope and a point, use the point slope form of the line. Substitute m = -1/3 and (5, -2).
[tex]y - y_1 = m(x-x_1)\\y --2 = -\frac{1}{3}(x - 5)\\y + 2 = -\frac{1}{3}(x-5)[/tex]
You can convert to slope intercept form.
[tex]y + 2 = -\frac{1}{3}(x-5)\\y + 2 = -\frac{1}{3}x + \frac{5}{3}\\y = -\frac{1}{3}x + \frac{5}{3} -2\\y = -\frac{1}{3}x - \frac{1}{3}[/tex]
