Answer:
[tex]x=t[/tex]
[tex]y=\pm\sqrt{3t-t^2}[/tex]
Step-by-step explanation:
The given polar equation is;
[tex]r=3\sin \theta[/tex]
We multiply both sides by r
[tex]r^2=3r\sin \theta[/tex]
The corresponding rectangular equation is
[tex]y^2+x^2=3x[/tex]
[tex]y^2=3x-x^2[/tex]
[tex]y=\sqrt{3x-x^2}[/tex]
Let x=t,
Then;
[tex]y=\pm \sqrt{3t-t^2}[/tex]
