Answer:
8
Step-by-step explanation:
We want to evaluate the function f(x) = 3(log to the base 2 of x) + (log to the base 2 of 1/x) at x = 16.
Note that 2^4 = 16, so (log to the base 2 of 16) is 4.
Also note that 1/16 = 1/(2^4), so (log to the base 2 of 1/(2^4 is -4.
In summary, f(x) = 3(log to the base 2 of x) + (log to the base 2 of 1/x) at x = 16 is equal to 3(4) -4, or 8.
