For this case we have the following system of equations:
[tex]8x-9y = -122\\-8x-6y = -28[/tex]
To solve, we add both equations:
[tex]8x-8x-9y-6y = -122-28\\-15y = -150\\y = \frac {-150} {- 15}\\y = 10[/tex]
We find the value of "x":
[tex]8x = -122 + 9y\\x = \frac {-122 + 9y} {8}\\x = \frac {-122 + 9 (10)} {8}\\x = \frac {-122 + 90} {8}\\x = \frac {-32} {8}\\x = -4[/tex]
The solution is (-4,10)
ANswer:
Option C
