For this case we have the following system of equations:
[tex]-2x + 5y = -3\\y-15 = 3x[/tex]
We multiply the second equation by -5:
[tex]-5y + 75 = -15x[/tex]
Now we add the equations:
[tex]-2x-5y + 5y + 75 = -3-15x\\-2x + 75 = -3-15x\\-2x + 15x = -75-3\\13x = -78\\x = \frac {-78} {13}\\x = -6[/tex]
We find the value of the variable "y":
[tex]y = 3x + 15\\y = 3 (-6) +15\\y = -18 + 15\\y = -3[/tex]
THE solution is: (-6, -3)
Answer:
(-6, -3)
