Answer:
[tex]\large\boxed{\dfrac{5}{11}}[/tex]
Step-by-step explanation:
[tex]\text{Use}\ P(A\ \cup\ B)=P(A)+P(B)-P(A\ \cap\ B).\\\\\text{We have:}\\\\P(A)=\dfrac{4}{11},\ P(B)=\dfrac{3}{11},\ P(A\ \cup\ B)=\dfrac{2}{11}.\\\\\text{Substitute:}\\\\\dfrac{2}{11}=\dfrac{4}{11}+\dfrac{3}{11}-P(A\ \cap\ B)\\\\\dfrac{2}{11}=\dfrac{7}{11}-P(A\ \cap\ B)\qquad\text{subtract}\ \dfrac{7}{11}\ \text{from both sides}\\\\-\dfrac{5}{11}=-P(A\ \cap\ B)\qquad\text{change the signs}\\\\P(A\ \cap\ B)=\dfrac{5}{11}[/tex]
