Answer:
[tex]\large\boxed{h(x)=x^3}[/tex]
Step-by-step explanation:
[tex]f(x)=(4x^2-11)^3\\\\f(x)=(h\circ g)(x)=h\bigg(g(x)\bigg)\to\text{exchange x to}\ g(x)=4x^2-11\\\\f(x)=(\underbrace{4x^2-11}_{g(x)})^3=\bigg(g(x)\bigg)^3=h\bigg(g(x)\bigg)\\\\\text{Therefore}\ h(x)=x^3[/tex]
