Answer:
Time required to completely fill this container = 78.43 seconds
Explanation:
Volume of container = 4 m³
Rate of filling of container = 0.051 m³/s
We have the equation
[tex]\texttt{Time required}=\frac{\texttt{Volume of container}}{\texttt{Rate of filling of container}}[/tex]
Substituting
[tex]\texttt{Time required}=\frac{4}{0.051}=\frac{4000}{51}=78.43 s[/tex]
Time required to completely fill this container = 78.43 seconds
