Answer:
[tex]\large\boxed{y=\dfrac{6}{r-3}}[/tex]
Step-by-step explanation:
[tex]\dfrac{5}{5}=1\\\\\dfrac{r}{3}-\dfrac{2}{y}=1\qquad\text{multiply both sides by 3}\\\\r-\dfrac{6}{y}=3\qquad\text{subtract}\ r\ \text{from both sides}\\\\-\dfrac{6}{y}=3-r\qquad\text{change the signs}\\\\\dfrac{6}{y}=r-3\\\\\dfrac{6}{y}=\dfrac{r-3}{1}\qquad\text{cross multiply}\\\\y(r-3)=(6)(1)\qquad\text{divide both sides by}\ (r-3)\neq0\\\\y=\dfrac{6}{r-3}[/tex]
