Answer:
0, π, 7π/6, 11π/6 on the interval 0 ≤ ø <2π.
Step-by-step explanation:
sinø + 1 = cos2ø
Use the identity cos 2o = 1 - 2 sin^2 o:
sin o + 1 = 1 - 2 sin^2 o
2sin^2 o + sin o + 1 - 1 = 0
2 sin^2 o + sin o = 0
sin o (2 sin 0 + 1) = 0
Therefore sin o = 0 or sin o = -1/2.
For sin o = 0 , o = 0, π radians.
For sin o = - 1/2, o = 7π/6, 11π/6 radians.
