Answer:
The dimensions of constant C are of [tex][L^{3}T]^{-4}[/tex]
Step-by-step explanation:
It is given that
[tex]V(t)=A+Bt+Ct^{3}[/tex]
Since the dimensions of volume are [tex][L^{3}][/tex]
Each of the term shall have a dimension of [tex][L^{3}][/tex] since they are in addition.
Thus for third term we can write
Thus we have
[tex][L^{3}]=[C][T^{4}]\\\\\therefore [C]=[L^{3}][T^{-4}][/tex]
