Answer:
[tex]y= x^{3} +4x^{2}-7x-28[/tex]
Step-by-step explanation:
We have to find a cubic function of x whose zeros are at x = √7, x = -√7 and at x = -4.
Therefore, the factors of the function will be (x - √7), (x + √7), and (x + 4)
Hence, the equation will be y = (x - √7) (x + √7) (x + 4)
⇒ [tex]y = (x^{2} -7)(x +4)[/tex]
⇒ [tex]y= x^{3} +4x^{2}-7x-28[/tex] (Answer)
