Answer:
See explanation
Step-by-step explanation:
Consider two triangles ABF and EDF. These triangles are two right triangles, because angles B and D are right anges.
In these triangles,
- ∠ABF ≅ ∠EDF - as two right angles;
- BF ≅ FE - given;
- ∠AFB ≅ ∠EFD - as vertical angles when two lines AD and BE itersect.
By ASA postulate (or HA postulate) these triangles are congruent, so
ΔABF ≅ ΔEDF
Congruent triangles have congruent corresponding parts, so
FA ≅ EF
