Answer:
Part 1) [tex]\frac{a^4}{4b^2}[/tex]
Part 2) [tex]-\frac{v^9}{w^6}[/tex]
Step-by-step explanation:
we know that
When divide exponents (or powers) with the same base, subtract the exponents
Part 1) we have
[tex]\frac{3a^{2}b^{-4}}{12a^{-2}b^{-2}}=(\frac{3}{12})(a^{2+2})(b^{-4+2} )=\frac{1}{4}a^{4}b^{-2}=\frac{a^4}{4b^2}[/tex]
Part 2) we have
[tex]\frac{v^3w^{-3}}{-v^{-6} w^3} =-v^{3+6}w^{-3-3}=-v^9w^{-6}=-\frac{v^9}{w^6}[/tex]
