Answer:
A'(-16,4), B'(16,-12), C'(8,12), D'(-4,16)
Step-by-step explanation:
The dilation with a center of dilation at (0,0) and scale factor of [tex]\frac{1}{4}[/tex] has the rule
[tex](x,y)\rightarrow \left(4x,4y\right)[/tex]
Quadrilateral ABCD has vertices at points A(-4,1), B(4,-3), C(2,3) and (-1,4).
Therefore, the image vertices are
- [tex]A(-4,1)\rightarrow A'(-16,4);[/tex]
- [tex]B(4,-3)\rightarrow B'(16,-12);[/tex]
- [tex]C(2,3)\rightarrow C'(8,12);[/tex]
- [tex]D(-1,4)\rightarrow D'(-4,16).[/tex]
