walae
walae walae
  • 04-12-2019
  • Mathematics
contestada

Write an equation of the line that passes through the points
(0, 3) and (-5, 0).

Respuesta :

Yang100
Yang100 Yang100
  • 04-12-2019

Answer:

y-3=3/5x

Step-by-step explanation:

y-y1=m(x-x1)

Where m=slope and (x1, y1) is a point on the line.

m=(y2-y1)/(x2-x1)

m=(0-3)/(-5-0)

m=-3/-5

m=3/5

y-3=3/5(x-0)

y-3=3/5(x)

y-3=3/5x

Answer Link
Lidpras
Lidpras Lidpras
  • 04-12-2019

(0, 3) is the y-intercept as it passes through y = 3 at x = 0, or the y-axis.

Slope:

[tex] \frac{y1 - y0}{x1 - x0} = \frac{3 - 0}{0 - ( - 5)} = \frac{3}{5} [/tex]

Equation of a straight line:

y = mx + c

m = slope (3/5)

c = y value of y-intercept (3)

Equation:

[tex]y = \frac{3}{5} x + 3[/tex]

Answer Link

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