Miznatnasah Miznatnasah 02-01-2020 Mathematics contestada Solve for y in terms of x: [tex]4 {x}^{2} + 8 {x}^{2}y = 8 {x}^{3} [/tex]A. [tex] \frac{2}{2x - 1} [/tex]B. [tex] \frac{2}{2x + 1} [/tex]C. [tex] \frac{2x - 1}{2} [/tex]D. [tex] \frac{2}{2x - 1} [/tex]
