Answer: False.
Step-by-step explanation:
For any random variable x,
Formula to calculate the z-score : [tex]z=\dfrac{x-\mu}{\sigma}[/tex]
, where [tex]\mu[/tex] = Mean
[tex]\sigma[/tex] = Standard deviation
Let x be the data point has a corresponding z-score of -1.5.
Then , we have
[tex]-1.5=\dfrac{x-\mu}{\sigma}[/tex]
[tex]-1.5\sigma=x-\mu[/tex]
[tex]\mu-1.5\sigma=x[/tex]
i.e. x is one and a half standard deviations below the mean value.
( one and a half =[tex]1+\dfrac{1}{2}=1.5[/tex] )
Therefore , the given statement is false.
