[tex]log_{x}(1/8)=-3/2[/tex]
This is equal to...
[tex]x^{-3/2}=1/8[/tex]
We want "x" so we need to isolate it using laws of exponents...
[tex]x^{(-1)(3/2)}=1/8[/tex]
[tex]x^{3/2}=8[/tex] because [tex]x^{-a}=1/x^{a}[/tex]
[tex]x=\sqrt[3]{8^{2}}[/tex] because [tex]x^{a/b}=\sqrt[b]{x^{a}}[/tex]
x = 4
answer: B
