Answer:
[tex]\huge\boxed{y=-\dfrac{1}{3}}[/tex]
Step-by-step explanation:
[tex]5=3y+6\qquad\text{subtract 6 from both sides}\\\\5-6=3y+6-6\\\\-1=3y\qquad\text{divide both sides by 3}\\\\\dfrac{-1}{3}=\dfrac{3y}{3}\\\\-\dfrac{1}{3}=y\to y=-\dfrac{1}{3}[/tex]
