Answer:
[tex]x=1[/tex]
Step-by-step explanation:
Here first open the inner parentheses and use the distributive property,
[tex]4(x+5)=4x+20\\\\(x+4(x+5))=(x+4x+20)=(5x+20)\\\\3(x+4(x+5))=3(5x+20)=15x+60\\\\(x+3(x+4(x+5)))=(x+15x+60)=16x+60\\\\2(x+3(x+4(x+5)))=2(16x+60)=32x+120\\\\x+2(x+3(x+4(x+5)))=x+32x+120=33x+120\\\\\\Hence\ x+2(x+3(x+4(x+5)))=x+32x+120=33x+120\\\\\Rightarrow 33x+120=153\\\\33x=153-120\\\\33x=33\\\\x=1[/tex]
