Therefore the inequality is x≤11
and maximum I can withdraw 11 bills.
Step-by-step explanation:
Given ,
Current balance $320
Minimum balance $100
I could spent =$(320-100) = $220
Let the number of bills be x.
Total amount of x bills = $20x
According to the problem,
20x≤ 220
⇔x ≤ [tex]\frac{220}{20}[/tex]
⇔x≤11
Therefore the inequality is x≤11
and maximum I can withdraw 11 bills.
