Answer:
6(8x +7)(x -4)
Step-by-step explanation:
6(8x^2 -25x -28) = 6(8x^2 -32x +7x -28) . . . . rewrite the middle term
= 6(8x(x -4) +7(x -4)) . . . . factor by grouping
= 6(8x +7)(x -4)
_____
To rewrite the middle term, you are looking for factors of (8)(-28) that have a sum of -25. The sum will be odd only if one of the factors is odd. The only odd factor in the product is 7, so we choose (8)(-28) = (7)(-32). Those two factors, 7 and -32, have a sum of -25, so those are the ones we used.
