Step-by-step explanation:
[tex] \because \cos \: \angle P = \frac{PQ}{OP} \\ \\ \therefore \: \cos \: \angle P = \frac{3.6}{9.1} \\ \\ \therefore \: \cos \: \angle P = 0.3956 \\ \\ \therefore \: \cos \: \angle P = \cos \: 66.6966 \\ \\ \huge \red{ \boxed{\therefore \: \angle P = 66.7 \degree}}[/tex]
