Answer:
Quotient given:
\frac{6-3 \sqrt[3]{6} }{ \sqrt[3]{9} }
Answer:
2 \sqrt[3]{3} - \sqrt[3]{18}
Explanation:
1) Rationalize by multiplying numerator and denominator by \sqrt[3]{9}
2)
\frac{6-3 \sqrt[3]{6} }{ \sqrt[3]{9} } \frac{\sqrt[3]{9}}{\sqrt[3]{9}}
3) Due the operations
\frac{6 \sqrt[3]{3}-3 \sqrt[3]{6.3}}{ \sqrt[3]{27} }
\frac{6 \sqrt[3]{3}-3 \sqrt[3]{6.3}}{ 3 }=2 \sqrt[3]{3} - \sqrt[3]{18}
Step-by-step explanation:
