Respuesta :

[tex]\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r = 2\\ h = 9 \end{cases}\implies V=\cfrac{\pi (2)^2(9)}{3}\implies V=12\pi \implies V\approx 37.7[/tex]

Otras preguntas