Answer:
Na5O4H10S
Explanation:
Data obtained from the question include:
Sodium (Na) = 11g
Hydrogen (H) = 0.9g
Oxygen (O) = 5.86g
Sulphur (S) = 2.94g
To obtain the empirical formula, do the following.
First Divide the above by their individual molar mass
Na = 11/23 = 0.478
H = 0.9/1 = 0.9
O = 5.86/16 = 0.366
S = 2.94/32 = 0.092
Next, divide by the smallest number
Na = 0.478/0.092 = 5
H = 0.9/0.092 = 10
O = 0.366/0.092 = 4
S = 0.092/0.092 = 1
Therefore, the empirical formula is Na5O4H10S
