Answer:
3041.5L
Explanation:
Data obtained from the question include:
V1 (initial volume) = 2785 L
P1 (initial pressure) = 830mmHg
P2 (final pressure) = stp = 760mmHg
V2 (final volume) =?
Applying the Boyle's law equation P1V1 = P2V2, the final volume propane can be achieved by as illustrated below:
P1V1 = P2V2
830 x 2785 = 760 x V2
Divide both side by 760
V2 = (830 x 2785)/760
V2 = 3041.5L
Therefore, the volume of the propane at standard pressure is 3041.5L
