Given:
Quadrilateral PQRS is a rhombus.
To find:
The value of y.
Solution:
In the rhombus PQRS,
PS = 10y and SR = y + 45
Property of rhombus:
All sides are congruent.
⇒ PS = SR
⇒ 10y = y + 45
Subtract y from both sides.
⇒ 10y - y = y + 45 - y
⇒ 9y = 45
Divide by 9 on both sides.
[tex]$\Rightarrow \frac{9y}{9} =\frac{45}{9}[/tex]
⇒ y = 5
The value of y is 5.
