Answer:
[tex]\frac{x-3}{x-5}[/tex]
Step-by-step explanation:
Factorise the numerator and denominator
x² - x - 6 = (x - 3)(x + 2)
x² - 3x - 10 = (x - 5)(x + 2)
The rational expression can now be written as
= [tex]\frac{(x-3)(x+2)}{(x-5)(x+2)}[/tex] ← cancel the factor (x + 2) on numerator/denominator
= [tex]\frac{x-3}{x-5}[/tex]
