tapiacelina tapiacelina

01-05-2020
Chemistry

contestada

To how much water should 250 mL of 12 M hydrochloric acid be added to
produce a 4.0 M solution?

Respuesta :

drpelezo drpelezo

01-05-2020

Answer:

500ml water

Explanation:

Molarity x Volume in liters (concentrated soln) = Molarity x Volume (diluted soln) ∴

250ml X 12M HCl = 4M x Volume of diluted solution

=> Volume of diluted solution = (250ml)(12M)/(4m) = 750 ml final solution vol. after mixing.

So the amount of water added to the 250ml of 12M acid = 750ml - 250ml = 500ml of water.

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