Answer:
[tex](x-13)^2+(y+13)^2=16[/tex]
Step-by-step explanation:
The equation of a circle is [tex](x-h)^2+(y-k)^2=r^2[/tex].
The center of a circle is written in the format (h, k).
So, it is given that h = 13, k = -13, and r = 4.
Substituting the values into the formula above gets us the following,
[tex](x-13)^2+(y+13)^2=16[/tex]
