Answer:
here is the answer
Step-by-step explanation:
her for first question
take
cos 63°=(3/X)
…
from which u will get x
now..
apply pythagoras formulae..for HI
HI =
[tex] \sqrt{x {}^{2} - 3 { }^{2} } [/tex]
And u will get.. HI
now.. for 3rd
take.
tan 55° =(y/22)
and.. u will get y
...
now for last..
again use pythagora formulae..for NM
NM =
[tex] \sqrt{y {}^{2} + 22 {}^{2} } [/tex]
i think u would solve it now
