Answer:
None of the options are correct. The correct answer is 30020J
Explanation:
Data obtained from the question include:
Mass (M) = 2000g
Initial temperature (T1) = 10°C
Final temperature (T2) = 29°C
Change in temperature (ΔT) = T2 - T1 = 29°C - 10°C = 19°C
Heat (Q) =?
Specific heat capacity (C) of granite = 0.79J/g°C
Applying the equation Q = MCΔT, the heat absorbed by the granite rock can be obtained as follow:
Q = MCΔT
Q = 2000 x 0.79 x 19
Q = 30020J
