Answer:
[tex]x=\pm\sqrt{2}[/tex]
Step-by-step explanation:
This system of equations is convenient, because the second equation already expresses y in terms of x. Now, you can substitute that in.
[tex]-2x^2-3x^2+5=-5[/tex]
Multiplying both sides by -1 and bringing the 5 over:
[tex]2x^2+3x^2-10=0[/tex]
Combining like terms and factoring out 5:
[tex]5(x^2-2)=0[/tex]
Factoring:
[tex]5(x-\sqrt{2})(x+\sqrt{2})=0[/tex]
Solutions: [tex]x=\pm\sqrt{2}[/tex]
Hope this helps!
